GDS to PA :- Time and Work with 50 MCQ with explanation
Time and Work |
(i) Suppose A can finish a piece of work in 8 days.
Then, work done by A in 1 day = ¹/₈ [by unitary method].
(ii) Suppose that the work done by A in 1 day is ¹/₆ Then, time taken by A to finish the whole work = 6 days.
General Rules
(i) Suppose if a person A can finish a work
in n days.
Then, work done by A in 1 day = 1/náµ—Ê° part of the
work.
(ii) Suppose that the work
done by A in 1 day is 1n1n
Then, time taken by A to finish the whole work =
n days.
Formulas
Including Short Tricks:
# 1.If persons can do W1 work in
D1 days working T1 hours in a day and M2 Persons
can do W2 work in D2 days working T2 hours
in a day then the relationship between them is
Example: - 12 persons can make 20 toys in 10 days
working 12 hours a day. Then in how many days can 24 persons make 32 toys
working 16 hours a day?
Problems on Time and Work :
1. Aaron alone can finish a piece of work
in 12 days and Brandon alone can do it in 15 days. If both of them work at it
together, how much time will they take to finish it?
Solution:
Time taken by Aaron to finish the work = 12 days.
Work done by Aaron in 1 day = ¹/₁₂
Time taken by Brandon to finish the work =
15 days.
Work done by Brandon in 1 day = ¹/₁₅
Work done by (Aaron + Brandon) in 1 day = ¹/₁₂ + ¹/₁₅ = ⁹/₆₀ = ³/₂₀
Time taken by (Aaron + Brandon) to finish the work = 20/6 days, i.e., 6²/₃ days.
Hence both can finish the
work in 6²/₃ days.
2. A and B together can do a piece of work
in 15 days, while B alone can finish it 20 days. In how many days can A alone
finish the work?
Solution:
Time taken by (A + B) to finish the work = 15 days.
Time taken by B alone to finish the work 20 days.
(A + B)’s 1 day’s work = ¹/₁₅
and B’s 1 day’s work = ¹/₂₀
A’s 1 day’s work = {(A + B)’s 1 day’s work} - {B’s 1 day’s work}
= (¹/₁₅ - ¹/₂₀) = (4 - 3)/60 = ¹/₆₀
Therefore, A alone can finish the work in 60 days.
3. A can do a piece of
work in 25 days and B can finish it in 20 days. They work together for 5 days
and then A leaves. In how many days will B finish the remaining work?
Solution:
Time taken by A to finish the work = 25 days.
A’s 1 day’s work = ¹/₂₅
Time taken by B to finish the work = 20 days.
B’s 1 day’s work = ¹/₂₀
(A + B)’s 1 day’s work = (¹/₂₅ + ¹/₂₀) = ⁹/₁₀₀
(A + B)’s 5 day’s work (5 × ⁹/₁₀₀) = 4̶5̶/1̶0̶0̶ = ⁹/₂₀
Remaining work (1 - ⁹/₂₀) = ¹¹/₂₀
Now, ¹¹/₂₀ work is done by B in 1 day
Therefore, ¹¹/₂₀ work will be done by B in (11/2̶0̶ × 2̶0̶) days = 11 days.
Hence, the remaining work is done by B in 11 days.
4. A and B
can do a piece of work in 18 days; B and C can do it in 24 days while C and A
can finish it in 36 days. If A, B, C works together, in how many days will they
finish the work?
Solution:
Time taken by (A + B) to finish the work = 18 days.
(A + B)’s 1 day’s work = ¹/₁₈
Time taken by (B + C) to finish the work = 24 days.
(B + C)’s 1 day’s work = ¹/₂₄
Time taken by (C + A) to finish the work = 36 days.
(C + A)’s 1 day’s work = ¹/₃₆
Therefore, 2(A + B + C)’s 1 day’s work = (¹/₁₈ + ¹/₂₄ + ¹/₃₆) = (4 + 3 + 2)/72
= 9/72 = ¹/₈
⇒ (A + B + C)’s 1 day’s work = (¹/₂ × ¹/₈) = ¹/₁₆
Therefore, A, B, C
together can finish the work in 16 days.
5.If A & B can complete a work in
days and A alone can finish that work in days then number of days required by B
to complete the work–
Example: - A & B together can do a piece of work in
days and A alone can do it in 18 days. In how many days can B alone do it?
6.If A can do a work in days and B can do faster than A, then B will
complete the work in -
Example: - Komal can do a work in days and Pooja is more efficient than Komal to
complete the same work, then find the total time taken to complete the work by
Pooja?
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